The molality of a solution that contains 36.6 g of NaCl in 200.0 g of water is _____ m. (Molar mass of NaCl = 58.44 g/mol)
A) 3.66
B) 3.13
C) 31.3
D) 36.6
E) 0.36

Question

Quizplus · Accepted Answer

Molality is defined as the number of moles of solute per kilogram of solvent.

First, we need to convert the mass of NaCl to moles:

mol NaCl = 36.6 g / 58.44 g/mol = 0.626 mol NaCl

Next, we need to convert the mass of water to kilograms:

mass of water = 200.0 g = 0.2 kg

Now we can calculate molality:

molality = 0.626 mol NaCl / 0.2 kg water = 3.13 m

The Molality of a Solution That Contains 36