If the pK_b of a conjugate base is equal to 10.9 at $45.0 ^ { \circ } \mathrm { C }$ , the value of its K_b is _____.

Question

Quizplus · Accepted Answer

The pKa of a conjugate acid is related to the pKb of its conjugate base by the equation pKa + pKb = 14 (at 25°C, but assuming the relationship holds approximately at 45°C for this question). Given pKb = 10.9, pKa = 14 - 10.9 = 3.1. The Ka (acid dissociation constant) can be found using the formula Ka = 10^(-pKa), which gives Ka = 10^(-3.1) = 1.26 × 10^-11.

If the PKb of a Conjugate Base Is Equal to 10.9

If the PK_b of a Conjugate Base Is Equal to 10.9