If the concentrations of the hydronium ion and hydroxide ion are equal to 1.025 × $10 ^ { - 7 }$ M each, the ion-product constant of liquid water is _____.

Question

Quizplus · Accepted Answer

The ion-product constant of liquid water, also known as the autoprotolysis constant, is given by the expression: Kw = [H3O+][OH-].
Since the concentrations of both hydronium and hydroxide ions are equal (1.025 × 10^-7 M), we can substitute this value into the Kw expression: Kw = (1.025 × 10^-7 M) × (1.025 × 10^-7 M) = 1.051 × 10^-14. Therefore, the answer is choice A.

If the Concentrations of the Hydronium Ion and Hydroxide Ion 10−710 ^ { - 7 }10−7

If the Concentrations of the Hydronium Ion and Hydroxide Ion $10 ^ { - 7 }$