In the cross AaBbCc × AaBbCc, what is the probability of producing the genotype AABBCC?
A) 1/4
B) 1/8
C) 1/16
D) 1/32
E) 1/64

Name: In the cross AaBbCc × AaBbCc, what is the probability of producing the genotype AABBCC? A) 1/4 B) 1/8 C) 1/16 D) 1/32 E) 1/64
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Question

Quizplus · Accepted Answer

Each gene pair (Aa, Bb, Cc) follows Mendelian inheritance with a 1/4 chance of producing the homozygous dominant genotype (AA, BB, or CC). Therefore, the probability of AABBCC is 1/4 * 1/4 * 1/4 = 1/64.

In the Cross AaBbCc × AaBbCc, What Is the Probability