Factor:
E) Nonfactorable over the integers

Question

Factor: 
E) Nonfactorable over the integers

Quizplus · Accepted Answer

We can try to find a common factor between the first and second half of the polynomial. Notice that the first half, 11eb69da_9ead_f68c_af94, ends in 4 and the second half, 5b77800f7978, starts with 5. These two digits have a difference of 1, which suggests that the missing digit in the middle of the polynomial is either 6 or 7. Trying these two possibilities, we get:

- If the missing digit is 6, we have 11eb69da_9ead_f686_af94_35b36f622ff6_TB8311_11, which is not factorable.
- If the missing digit is 7, we have 11eb69da_9ead_f687_af94_f04bca4ea80a_TB8311_11, which is not factorable.
- If the missing digit is 8, we have 11eb69da_9ead_f68d_af94_35b36f622ff6_TB8311_11, which is a possible factorization.

Therefore, choice A is the best option.