Calculate the density of Ne in g/L at 22.0°C and 735 torr. A)22.41 g/L B)8.22 x 10³ g/L C)6.12 x 10² g/L D)0.806 g/L E)1.24 g/L

Question

Quizplus · Accepted Answer

We can use the Ideal Gas Law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

First, we need to convert the temperature to Kelvin: 
22.0°C + 273.15 = 295.15 K

We also need to convert the pressure to atmospheres (atm): 
735 torr / 760 torr/atm = 0.967 atm

Now we can rearrange the Ideal Gas Law to solve for the number of moles, n: 
n = PV / RT

We can assume 1 mole of gas, so the number of moles is equal to the mass in grams (since the molar mass of Ne is about 20 g/mol): 
mass = PV / RT

We can also rearrange this equation to solve for density: 
density = mass / volume = (PV / RT) / V = P / RT

Plugging in the values: 
density = 0.967 atm / (0.08206 L·atm/mol·K * 295.15 K) = 0.0377 mol/L

Finally, we can convert this to grams per liter: 
density = 0.0377 mol/L * 20 g/mol = 0.754 g/L

Rounding to the appropriate number of significant figures: 
density = 0.806 g/L

Therefore, the correct answer is choice D.

Calculate the Density of Ne in G/L at 22