Given a fixed amount of gas in a rigid container (no change in volume), what pressure will the gas exert if the pressure is initially 1.50 atm at 22.0°C, and the temperature is changed to 11.0°C?
A)0.750 atm
B)3.00 atm
C)1.56 atm
D)1.44 atm
E)301 atm

Question

Quizplus · Accepted Answer

The pressure-temperature relationship of a gas is described by the Ideal Gas Law:

PV = nRT

where P is the pressure, V is the volume, n is the amount of substance, R is the gas constant, and T is the absolute temperature.

Since the container is rigid, the volume is constant, and we can write:

P1/T1 = P2/T2

where P1 and T1 are the initial pressure and temperature, and P2 and T2 are the final pressure and temperature.

We are given:

P1 = 1.50 atm
T1 = 22.0°C + 273.15 = 295.15 K
T2 = 11.0°C + 273.15 = 284.15 K

Substituting these values, we can solve for P2:

P2 = P1 x (T2/T1) = 1.50 atm x (284.15 K/295.15 K) = 1.44 atm

Therefore, the answer is (D) 1.44 atm.

Given a Fixed Amount of Gas in a Rigid Container