When a 25.00 mL sample of NaOH is titrated with 0.4523 M H₂SO₄, 36.69 mL of H₂SO₄ solution is required to neutralize the NaOH. What is the molarity of the NaOH? A)0.3319 M B)0.6638 M C)1.328 M D)0.6164 M E)0.1988 M

Question

Quizplus · Accepted Answer

First, we need to use the equation:

Molarity (M) = moles of solute / volume of solution in liters

We know the volume of the NaOH solution is 25.00 mL, or 0.02500 L. We also know the volume of the H2SO4 solution (which we assume completely reacts with the NaOH) is 36.69 mL, or 0.03669 L, and the molarity of the H2SO4 solution is 0.4523 M.

Using stoichiometry, we can determine the amount of moles of NaOH in the reaction:

1 mole H2SO4 reacts with 2 moles NaOH

So, moles of NaOH = 0.4523 M * 0.03669 L * (2 moles NaOH / 1 mole H2SO4) = 0.03319 moles NaOH

Finally, we can plug this value into our equation:

Molarity of NaOH = 0.03319 moles NaOH / 0.02500 L NaOH = 1.328 M

Therefore, the correct answer is C.

When a 2500 ML Sample of NaOH Is Titrated with 0