What is the molal concentration of ions in a 2.40 m solution of Al(NO₃)₃? A)2.40 m B)7.20 m C)9.60 m D)0.800 m E)31.2 m

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Quizplus · Accepted Answer

Al(NO₃)₃ is a strong electrolyte and dissociates completely into its ions in solution. The formula for Al(NO₃)₃ is not given, but we can assume it follows the pattern of other ionic compounds, such as NaCl. In a 2.40 m solution of an ionic compound, there are 2.40 moles of the compound per liter of solution. Each mole of this compound will dissociate into multiple ions, so the molal concentration of ions will be greater than 2.40 m. To find the exact molal concentration of ions, we need to know how many ions are produced by each mole of the compound when it dissociates. Without this information, we cannot calculate the exact molal concentration of ions. However, we can make an estimate. If we assume the formula for Al(NO₃)₃ is similar to NaCl, then each mole of the compound will dissociate into 2 ions (1 Al ion and 1 (NO₃)₃ ion). Therefore, the molal concentration of ions would be 2 x 2.40 m = 4.80 m. However, it is important to note that this is just an estimate and the actual molal concentration of ions could be different depending on the formula of the compound. The closest answer choice to our estimate is C) 9.60 m.

What Is the Molal Concentration of Ions in a 2