Calculate the pOH of a solution that has [OH^-] = 5.9 × 10^-5 M. A)pOH = 5.90 B)pOH = 5.00 C)pOH = 4.23 D)pOH = 5.59 E)pOH = 9.77

Name: Calculate the pOH of a solution that has [OH - ] = 5.9 × 10 -5 M. A)pOH = 5.90 B)pOH = 5.00 C)pOH = 4.23 D)pOH = 5.59 E)pOH = 9.77
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Quizplus · Accepted Answer

pOH = -log[OH-] [OH-] can be found by using Kw = [H+][OH-] = 1.0 x 10^-14 [H+] = [OH^-] = 5.9 x 10^-6 M [OH-] = Kw/[H+] = 1.0 x 10^-14 / 5.9 x 10^-6 = 1.69 x 10^-9 M pOH = -log(1.69 x 10^-9) = 4.23. Therefore, the answer is C.

Calculate the POH of a Solution That Has [OH-] =

Calculate the POH of a Solution That Has [OH^-] =