A CD has a diameter of 12.0 cm. If the CD starts from rest and has a constant angular acceleration of 2.00 rad/sec^2, then the radial acceleration of a point 3.00 cm from the center of the CD after 3.00 sec is A) 0.950 m/s². B) 1.08 m/s². C) 1.25 m/s². D) 1.58 m/s². E) 1.83 m/s².

Question

Quizplus · Accepted Answer

The radial (centripetal) acceleration $a_r$ can be calculated using the formula $a_r = r\omega^2$, where $r$ is the radius from the center to the point of interest, and $\omega$ is the angular velocity. Given the constant angular acceleration $\alpha = 2.00 \, \text{rad/s}^2$, the angular velocity $\omega$ after time $t = 3.00 \, \text{s}$ can be found using $\omega = \alpha t = 2.00 \times 3.00 = 6.00 \, \text{rad/s}$. With $r = 3.00 \, \text{cm} = 0.03 \, \text{m}$, the radial acceleration is $a_r = 0.03 \times (6.00)^2 = 1.08 \, \text{m/s}^2$.

A CD Has a Diameter of 12