A horizontal force is applied to a 2.0 kg box. The box starts from rest, moves a horizontal distance of 12.0 meters, and obtains a velocity of 8.0 m/s. The change in the kinetic energy is
A) 32 J.
B) 48 J.
C) 50 J.
D) 58 J.
E) 64 J.

Question

Quizplus · Accepted Answer

The change in kinetic energy can be calculated using the formula for kinetic energy, which is $KE = \frac{1}{2}mv^2$, where $m$ is the mass and $v$ is the velocity. Initially, the box is at rest, so its initial kinetic energy is 0. The final kinetic energy, when the box has a velocity of 8.0 m/s, is $\frac{1}{2} \times 2.0 \, \text{kg} \times (8.0 \, \text{m/s})^2 = 64 \, \text{J}$. Therefore, the change in kinetic energy is $64 \, \text{J} - 0 \, \text{J} = 64 \, \text{J}$.

A Horizontal Force Is Applied to a 2