An 8.00 kg object has a moment of inertia of 1.50 kg m². If a torque of 2.00 N•m is applied to the object, the angular acceleration is A) 0.750 rad/s². B) 1.00 rad/s². C) 1.33 rad/s². D) 2.01 rad/s². E) 2.67 rad/s².

Question

Quizplus · Accepted Answer

We can use the equation τ = Iα (torque equals moment of inertia times angular acceleration) to solve for the angular acceleration. Rearranging the equation, we get: α = τ/I Plugging in the values given in the problem, we get: α = 2.00 N•m / 1.50 kg m² α = 1.33 rad/s² Therefore, the angular acceleration is 1.33 rad/s². The correct answer is choice C).

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