A 2.00 kg mass is connected to a spring with a spring constant of 9.00 N/m. The displacement is given by the expression x(t) = (12.0 cm) sin(ω t). What is the period of the simple harmonic motion?
A) 4.75 sec
B) 4.27 sec
C) 3.95 sec
D) 3.36 sec
E) 2.96 sec

Question

Quizplus · Accepted Answer

The angular frequency ω is given by ω = sqrt(k/m), where k is the spring constant and m is the mass. ω = sqrt(9/2) = 2.12 rad/s. The period T is given by T = 2π/ω = 2π/2.12 ≈ 2.96 sec.

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