A molecule in an ideal gas has an rms velocity 450 m/s. If the mean free path of the particle in the gas is 5.00 × 10^-8 m, then what is the average time between collisions? A) 1.11 × 10^-10 sec B) 1.98 × 10^-10 sec C) 2.03 × 10^-10 sec D) 2.56 × 10^-10 sec E) 3.03 × 10^-10 sec

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Quizplus · Accepted Answer

The average time between collisions ($t$) for a molecule in an ideal gas can be calculated using the formula $t = \frac{\lambda}{v_{rms}}$, where $\lambda$ is the mean free path and $v_{rms}$ is the root mean square velocity. Substituting the given values, $\lambda = 5.00 \times 10^{-8}$ m and $v_{rms} = 450$ m/s, we get $t = \frac{5.00 \times 10^{-8}}{450} = 1.11 \times 10^{-10}$ sec.

A Molecule in an Ideal Gas Has an Rms Velocity