One mole of an ideal gas freely expands from 1.00 liter to 2.00 liters. The change in entropy of the gas in the expansion is

Question

Quizplus · Accepted Answer

The change in entropy ($\Delta S$) for an ideal gas during a free expansion can be calculated using the formula $\Delta S = nR\ln\frac{V_f}{V_i}$, where $n$ is the number of moles, $R$ is the gas constant (8.314 J/mol·K), $V_f$ is the final volume, and $V_i$ is the initial volume. Substituting the given values (n = 1 mole, $V_f = 2.00$ liters, $V_i = 1.00$ liter), we get $\Delta S = 1 \times 8.314 \times \ln\frac{2.00}{1.00} = 8.314 \times \ln(2) \approx 5.76$ J/K, which rounds to 5.80 J/K, option A.

One Mole of an Ideal Gas Freely Expands from 1