A charged particle enters a region of uniform magnetic field at a speed of 2.8 × 10⁴ m/s, at an angle of 37 degrees relative to the magnetic field direction. What will be the magnitude of the component of the particle's velocity that is parallel to the magnetic field while it is in this region? A) Insufficient information is given. B) 2.2 × 10⁴ m/s C) 2.1 × 10⁴ m/s D) 1.7 × 10⁴ m/s E) 2.8 × 10⁴ m/s

Question

Quizplus · Accepted Answer

The component of the particle's velocity parallel to the magnetic field is found using the cosine of the angle (cos(37 degrees)) multiplied by the total velocity. Since the magnetic field only affects the perpendicular component of velocity, the parallel component remains unchanged. The calculation is $2.8 \times 10^{14} \times \cos(37^\circ) \approx 2.2 \times 10^{14}$ m/s.

A Charged Particle Enters a Region of Uniform Magnetic Field