How does Brewster's angle for a given interface compare to the critical angle for total internal reflection from the same surface (assuming n2

Question

How does Brewster's angle for a given interface compare to the critical angle for total internal reflection from the same surface (assuming n2 < n1, so that total internal reflection is possible)?
A) Brewster's angle is always greater than the critical angle.
B) Brewster's angle can be either greater than or less than the critical angle.
C) Brewster's angle is always less than the critical angle.
D) The two angles are always equal.

Quizplus · Accepted Answer

Brewster's angle is given by tanθp = n2/n1, where θp is the angle of incidence for which the reflected light is completely polarized and n1 and n2 are the refractive indices of the two media. The critical angle for total internal reflection is given by sinθc = n2/n1. Since sinθc > tanθp, it follows that Brewster's angle is always less than the critical angle. Therefore, the correct answer is C.

How Does Brewster's Angle for a Given Interface Compare to the Critical