What is the energy of a photon emitted in a transition from the n = 3 state to the n = 2 state in He⁺? A) 15.1 eV B) 7.56 eV C) 3.78 eV D) 2.12 eV E) 1.89 eV

Question

Quizplus · Accepted Answer

The energy of a photon emitted in a transition from the n = 3 state to the n = 2 state is given by: E = hc/λ = hc(1/λ_final - 1/λ_initial) where hc = 1240 eV*nm, λ_final is the wavelength of the emitted photon in nm, and λ_initial is the wavelength of the absorbed photon in nm. For He⁺, the initial state is the singlet state ^{and the final state is the singlet state}. We need to find the transition from the n = 3 state to the n = 2 state in this system. To do this, we use the energy level diagram for He⁺ (refer to a standard textbook or online source for this diagram). The energy difference between the n = 3 state and the n = 2 state is 7.56 eV, which corresponds to the energy of the emitted photon. Therefore, the answer is B.

What Is the Energy of a Photon Emitted in a Transition