Electrons are accelerated through a potential difference of 90.0 kV and directed at a tungsten target to produce x-rays. What is the cutoff frequency of the x-ray spectrum produced? A) 2.18 × 10¹⁹ Hz B) 2.10 × 10¹⁹ Hz C) 1.17 × 10²¹ Hz D) 9.25 × 10²¹ Hz E) 6.20 × 10¹⁵ Hz

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Quizplus · Accepted Answer

The cutoff frequency of the x-ray spectrum can be calculated using the equation $f = \frac{eV}{h}$, where $e$ is the charge of an electron (1.6 × 10^-19 C), $V$ is the potential difference (90,000 V), and $h$ is Planck's constant (6.626 × 10^-34 J·s). Substituting the given values, the calculation yields a frequency close to the value in option A, 2.18 × 10^19 Hz.

Electrons Are Accelerated Through a Potential Difference of 90