What accelerating potential in an electron microscope would give electrons a wavelength 1.00 × 10⁻¹⁰ m? A) 37.5 V B) 75.0 V C) 150 V D) 300 V

Question

Quizplus · Accepted Answer

The de Broglie wavelength of an electron is given by λ = h/p, where h is Planck's constant and p is the momentum of the electron. 
For electrons accelerated through a potential difference V, the momentum is given by p = sqrt(2m*e*V), where m is the mass of the electron and e is the electron's charge. 
Setting λ = 1.00 × 10^-10 m and solving for V, we get V = h^2/(2m*e*λ^2). Substituting the values gives V = 150V. Therefore, the answer is C.

What Accelerating Potential in an Electron Microscope Would Give Electrons