The salts X(NO₃)₂and Y(NO₃)₂ (where X⁺ and Y⁺ are metal ions) are dissolved in water to give a solution which is 0.1 M in each of them. Which of the answers gives the concentration of chloride ions will precipitate the most YCl₂ without precipitating any XCl₂? Given K_spvalues: XCl₂, 2 × 10⁻⁵YCl₂, 1 × 10⁻¹⁰ A)1 M Cl ⁻ B)0.1 M Cl ⁻ C)0.01 M Cl ⁻ D)0.001 M Cl ⁻ E)0.0001 M Cl ⁻

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Quizplus · Accepted Answer

To find the concentration of chloride ions that will precipitate YCl2 without precipitating XCl2, we use the solubility product constant (Ksp) formula: Ksp = [Metal ion][Cl-]^2. For XCl2, Ksp = 2 × 10^-15, and for YCl2, Ksp = 1 × 10^-10. Since the solution is 0.1 M in each metal ion, we set up the equation for YCl2 to precipitate first. For YCl2, 1 × 10^-10 = (0.1)[Cl-]^2, solving for [Cl-] gives [Cl-] = √(1 × 10^-10 / 0.1) = √(1 × 10^-9) = 1 × 10^-4.5 M. The closest option that will precipitate YCl2 without affecting XCl2 is 0.001 M Cl-, as it is slightly higher than the calculated concentration, ensuring precipitation of YCl2 while not exceeding the solubility of XCl2.

The Salts X(NO3)2 and Y(NO3)2 (Where X+ and Y+ Are

The Salts X(NO₃)₂and Y(NO₃)₂ (Where X⁺ and Y⁺ Are