Calculate the solubility of strontium fluoride, SrF₂, in pure water. K_sp = 2.6 × 10⁻⁹ A)1.4 × 10 ⁻³ M B)3.4 × 10 ⁻⁴ M C)8.7 × 10 ⁻⁴ M D)5.1 × 10 ⁻⁵ M E)

Question

Calculate the solubility of strontium fluoride, SrF₂, in pure water. K_sp = 2.6 × 10⁻⁹ A)1.4 × 10 ⁻³ M B)3.4 × 10 ⁻⁴ M C)8.7 × 10 ⁻⁴ M D)5.1 × 10 ⁻⁵ M E)< 1.0 × 10 ⁻⁵ M

Quizplus · Accepted Answer

Using the equation: K_sp = [Sr2+] [F-]2 We know that the value of K_sp for SrF₂ = 2.6 × 10⁻⁹ Now, let x be the solubility of strontium fluoride and assume that the amount dissociated is very small compared to the original undissociated amount, we can say that: [Sr2+] = x [F-] = x Substituting these values into the solubility product expression: 2.6 × 10⁻⁹ = x × x2 Solving for x: x = 8.7 × 10⁻⁴ Therefore, the solubility of strontium fluoride in pure water is 8.7 × 10⁻⁴ M.

Calculate the Solubility of Strontium Fluoride, SrF2, in Pure Water

Calculate the Solubility of Strontium Fluoride, SrF₂, in Pure Water