The iodine "clock reaction" involves the following sequence of reactions occurring in a reaction mixture in a single beaker. 1.IO₃(aq) + 5I⁻(aq) + 6H⁺(aq) → 3I₂(aq) + 3H₂O(l) 2.I₂(aq) + 2S₂O₃²⁻(aq) → 2I⁻(aq) + S₄O₆²⁻aq) The molecular iodine (I₂) formed in reaction 1 is immediately used up in reaction 2, so that no iodine accumulates. What is the overall reaction occurring in this experiment? A)IO ₃ ⁻( aq)+ 3I ⁻( aq)+ 2S ₂O3 ₂ ⁻ aq)+ 6H+( aq)→ 2I ₂( aq)+ S ₄O6 ₂ ⁻( aq)+ 3H ₂O( l) B)IO ₃( aq)+ 4S ₂O3 ₂ ⁻( aq)+ 6H+( aq)→ I ⁻( aq)+ 2S ₄O6 ₂ ⁻( aq)+ 3H ₂O( l) C)IO ₃⁻ aq)+ 6S ₂O3 ₂ ⁻ aq)+ 6H+( aq)→ I ^-( aq)+ 3S ₄O6 ₂ ⁻ aq)+ 3H ₂O( l) D)IO3 ⁻( aq)+ I2( aq)+ 8S2O32 ⁻( aq)+ 6H+( aq)→ 3I-( aq)+ 4S4O62 ⁻( aq)+ 3H2O( l) E)IO3( aq)+ 2I2( aq)+ 6S2O32 ⁻(aq)+ 6H+( aq)→ 5I ^-( aq)+ 3S4O62−( aq)+ 3H2O( l)

Question

Quizplus · Accepted Answer

The Answer of The iodine "clock reaction" involves the following sequence of reactions occurring in a reaction mixture in a single beaker. 1.IO₃(aq) + 5I⁻(aq) + 6H⁺(aq) → 3I₂(aq) + 3H₂O(l) 2.I₂(aq) + 2S₂O₃²⁻(aq) → 2I⁻(aq) + S₄O₆²⁻aq) The molecular iodine (I₂) formed in reaction 1 is immediately used up in reaction 2, so that no iodine accumulates. What is the overall reaction occurring in this experiment? A)IO ₃ ⁻( aq)+ 3I ⁻( aq)+ 2S ₂O3 ₂ ⁻ aq)+ 6H+( aq)→ 2I ₂( aq)+ S ₄O6 ₂ ⁻( aq)+ 3H ₂O( l) B)IO ₃( aq)+ 4S ₂O3 ₂ ⁻( aq)+ 6H+( aq)→ I ⁻( aq)+ 2S ₄O6 ₂ ⁻( aq)+ 3H ₂O( l) C)IO ₃⁻ aq)+ 6S ₂O3 ₂ ⁻ aq)+ 6H+( aq)→ I ^-( aq)+ 3S ₄O6 ₂ ⁻ aq)+ 3H ₂O( l) D)IO3 ⁻( aq)+ I2( aq)+ 8S2O32 ⁻( aq)+ 6H+( aq)→ 3I-( aq)+ 4S4O62 ⁻( aq)+ 3H2O( l) E)IO3( aq)+ 2I2( aq)+ 6S2O32 ⁻(aq)+ 6H+( aq)→ 5I ^-( aq)+ 3S4O62−( aq)+ 3H2O( l)

The Iodine "Clock Reaction" Involves the Following Sequence of Reactions