How many grams of sodium fluoride (used in water fluoridation and manufacture of insecticides) are needed to form 485 g of sulfur tetrafluoride? 3SCl₂(l) + 4NaF(s) → SF₄(g) + S₂Cl₂(l) + 4NaCl(s) A)1940 g B)1510 g C)754 g D)205 g E)51.3 g

Question

Quizplus · Accepted Answer

According to the balanced chemical equation:
3 moles of SCl2 require 4 moles of NaF
Molar mass of SCl2 = 102.97 g/mol
Molar mass of NaF = 41.99 g/mol

Let's first calculate the number of moles of SCl2 in 485 g:
n = m/M = 485/102.97 = 4.706 mol

Since 3 moles of SCl2 require 4 moles of NaF, we can calculate the number of moles of NaF required:
n(NaF) = (4/3) x n(SCl2) = (4/3) x 4.706 = 6.275 mol

Finally, we can calculate the mass of NaF required:
m(NaF) = n x M = 6.275 x 41.99 = 263.4 g

However, we must multiply by 4 (the coefficient of NaF in the balanced equation) to account for the fact that 4 moles of NaF are required for every 3 moles of SCl2:
m(NaF) = 263.4 g x 4 = 1053.6 g

Therefore, the closest answer choice is C: 754 g.

How Many Grams of Sodium Fluoride (Used in Water Fluoridation