Analysis of a carbohydrate showed that it consisted of 40.0 % C, 6.71 % H, and 53.3 % O by mass. Its molecular mass was found to be between 140 and 160 amu. What is the molecular formula of this compound?
A) C 4H 8O 6
B) C 5H 10O 5
C) C 5H 12O 5
D) C 6H 12O 4
E) None of these choices are correct.
Correct Answer:
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