A sample container of carbon monoxide occupies a volume of 435 mL at a pressure of 785 torr and a temperature of 298 K. What would its temperature be if the volume were changed to 265 mL at a pressure of 785 torr?
A)182 K
B)298 K
C)387 K
D)489 K
E)538 K

Question

Quizplus · Accepted Answer

Since the pressure and the amount of gas remain constant, the relationship between volume and temperature can be described by Charles's Law (V1/T1 = V2/T2). Solving for T2 gives T2 = (V2 * T1) / V1. Substituting the given values (V1 = 435 mL, T1 = 298 K, V2 = 265 mL) into the equation yields T2 = (265 mL * 298 K) / 435 mL = 182 K.

A Sample Container of Carbon Monoxide Occupies a Volume of 435