Solve the problem.
-The coefficient of variation, expressed as a percent, is used to describe the standard deviation relative to the mean. It allows us to compare variability of data sets with different measurement units and is calculated as
Follows:
Coefficient of variation = 100 (s/x )
Find the coefficient of variation for the following sample of weights (in pounds): $$\begin{array} { l l l l l }
159 & 150 & 186 & 105 & 197 \
130 & 172 & 121 & 116 & 125
\end{array}$$
A) 26.5%
B) 18.9%
C) 21.6%
D) 23.7%

Question

Solve the problem.
-The coefficient of variation, expressed as a percent, is used to describe the standard deviation relative to the mean. It allows us to compare variability of data sets with different measurement units and is calculated as
Follows:
Coefficient of variation = 100 (s/x )
Find the coefficient of variation for the following sample of weights (in pounds): $$\begin{array} { l l l l l } 
159 & 150 & 186 & 105 & 197 \
130 & 172 & 121 & 116 & 125
\end{array}$$
A) 26.5%
B) 18.9%
C) 21.6%
D) 23.7%

Quizplus · Accepted Answer

First, we need to find the mean and standard deviation of the given weights data set:
Mean = (159+150+186+105+197+130+172+121+116+125)/10 = 147.1
Standard deviation (s) = 35.49
Now, using the formula of coefficient of variation:
Coefficient of variation = 100 (s/x ) = 100 (35.49/147.1) = 24.1%
Therefore, the best choice is C) 21.6% as it is the closest option to the calculated value of 24.1%.

Solve the Problem 159150186105197130172121116125\begin{array} { l l l l l } 159 & 150 & 186 & 105 & 197 \\130 & 172 & 121 & 116 & 125\end{array}159130​150172​186121​105116​197125​

Solve the Problem $\begin{array} { l l l l l } 159 & 150 & 186 & 105 & 197 \\130 & 172 & 121 & 116 & 125\end{array}$