Analyze the following code:
A) The program compiles despite the semicolon (;) on the for loop line, and displays $ 4 . $
B). The program compiles despite the semicolon $ (;) $ on the for loop line, and displays $ 14 . $
C) The program has a compile error because of the semicolon $ (;) $ on the for loop line.
D) The program has a runtime error because of the semicolon (;) on the for loop line.

Question

Analyze the following code:  
A) The program compiles despite the semicolon (;) on the for loop line, and displays $ 4 . $ 
B). The program compiles despite the semicolon $ (;) $ on the for loop line, and displays $ 14 . $ 
C) The program has a compile error because of the semicolon $ (;) $ on the for loop line. 
D) The program has a runtime error because of the semicolon (;) on the for loop line.

Quizplus · Accepted Answer

The code represents a valid identifier, but it does not contain any executable statements. The for loop has a semicolon after the condition, which means that there is an empty statement inside the loop body. Therefore, the loop executes three times but does not execute any statements. The variable x is initialized to 1 and incremented by 1 in each iteration, so the final value of x is 4. After the loop, the value of x is added to 10, resulting in a final output of 14. There are no compilation or runtime errors in the code.

Analyze the Following Code: A) the Program Compiles 4. 4 . 4.

Analyze the Following Code:
A) the Program Compiles $4 .$