Analyze the following code fragments that assign a boolean value to the variable even. Code 1:
If (number % 2 == 0)
Even = true;
Else
Even = false;
Code 2:
Even = (number % 2 == 0) ? true: false;
Code 3:
Even = number % 2 == 0;
A) Code 3 has a syntax error, because you attempt to assign number to even.
B) Code 2 has a syntax error, because you cannot have true and false literals in the conditional expression.
C) All three are correct, but Code 1 is preferred.
D) All three are correct, but Code 2 is preferred.
E) All three are correct, but Code 3 is preferred.

Question

Quizplus · Accepted Answer

All three code fragments correctly assign a boolean value to the variable `even` based on whether `number` is even or not. Code 3 is the most concise and preferred way to achieve this, as it directly assigns the result of the boolean expression `number % 2 == 0` to `even` without the need for an if-else structure or a ternary operator.

Analyze the Following Code Fragments That Assign a Boolean Value