The numbers 1 through 7 are written in separate slips of paper, and the slips are placed into a box. Then, 4 of these slips are drawn at random.
What is the probability that the drawn slips are $\text { "1", "2", "3", and "4", }$ in that order?
A) 0.02857
B) 0.68568
C) 0.02856
D) 0.00119

Question

Quizplus · Accepted Answer

The probability of drawing "1", then "2", then "3", then "4" in that order is calculated by multiplying the probabilities of each draw happening in sequence. The probability of drawing "1" first is 1/7, then "2" is 1/6 (since one slip is already removed), then "3" is 1/5, and finally "4" is 1/4. Multiplying these probabilities gives (1/7) * (1/6) * (1/5) * (1/4) = 1/840, which is approximately 0.00119.

The Numbers 1 Through 7 Are Written in Separate Slips "1", "2", "3", and "4", \text { "1", "2", "3", and "4", } "1", "2", "3", and "4",

The Numbers 1 Through 7 Are Written in Separate Slips $\text { "1", "2", "3", and "4", }$