On a TV game show, a contestant is shown 11 products from a grocery store and is asked to choose the three least-expensive items in the set. The three chosen items need not be in any particular order.
In how many ways can the contestant choose the three items?
A) 6
B) 165
C) 6,652,800
D) 990

Question

Quizplus · Accepted Answer

The number of ways to choose 3 items out of 11 is calculated using the combination formula, which is C(n, k) = n! / [k!(n-k)!]. Here, n=11 and k=3, so the calculation is C(11, 3) = 11! / (3! * (11-3)!) = 165.

On a TV Game Show, a Contestant Is Shown 11