A geneticist is studying two genes. Each gene can be either dominant or recessive. A sample of 100 individuals is categorized as follows.

$\begin{array} { l c c }
& \begin{array} { c }
\text { Gene 2 } \
\text { Dominant }
\end{array} & \begin{array} { c }
\text { Gene 2 } \
\text { Recessive }
\end{array} \
\text { Gene 1 Dominant } & 14 & 26 \
\text { Gene 1 Recessive } & 21 & 39
\end{array}$

Given that gene 1 is dominant, what is the probability that gene 2 is dominant?
A) 0.35
B) 0.39
C) 0.40
D) 2.50

Question

A geneticist is studying two genes. Each gene can be either dominant or recessive. A sample of 100 individuals is categorized as follows.

$\begin{array} { l c c } 
& \begin{array} { c } 
\text { Gene 2 } \
\text { Dominant }
\end{array} & \begin{array} { c } 
\text { Gene 2 } \
\text { Recessive }
\end{array} \
\text { Gene 1 Dominant } & 14 & 26 \
\text { Gene 1 Recessive } & 21 & 39
\end{array}$

Given that gene 1 is dominant, what is the probability that gene 2 is dominant?
A) 0.35
B) 0.39
C) 0.40
D) 2.50

Quizplus · Accepted Answer

The probability that gene 2 is dominant given that gene 1 is dominant is calculated by dividing the number of individuals with both gene 1 and gene 2 dominant by the total number of individuals with gene 1 dominant. This gives $ \frac{14}{14 + 26} = \frac{14}{40} = 0.35 $.

A Geneticist Is Studying Two Genes Given That Gene 1 Is Dominant, What Is the Probability