Use the normal approximation to find the indicated probability. The sample size is n, the population proportion of successes is p, and X is the number of successes in the sample. $n = 91 , p = 0.61 : P ( X 53 )$
A) 0.6664
B) 0.6844
C) 0.6293
D) 0.3707

Question

Use the normal approximation to find the indicated probability. The sample size is n, the population proportion of successes is p, and X is the number of successes in the sample. $n = 91 , p = 0.61 : P ( X > 53 )$
A) 0.6664
B) 0.6844
C) 0.6293
D) 0.3707

Quizplus · Accepted Answer

The correct answer is A because the probability of getting more than 53 successes in a sample of 91 with a population proportion of successes of 0.61 is 0.6664.

Use the Normal Approximation to Find the Indicated Probability n=91,p=0.61:P(X>53)n = 91 , p = 0.61 : P ( X > 53 )n=91,p=0.61:P(X>53)

Use the Normal Approximation to Find the Indicated Probability $n = 91 , p = 0.61 : P ( X > 53 )$