Solve the problem.
-If an object is thrown upward with an initial velocity of $14 \mathrm { ft }$ per sec, then its height (in feet) is given by $h ( t ) = - 14 t ^ { 2 } + 56 t$ after time $t$ seconds. What is its maximum height?
A) $198 \mathrm { ft }$
B) $56 \mathrm { ft }$
C) $28 \mathrm { ft }$
D) $196 \mathrm { ft }$

Question

Quizplus · Accepted Answer

The maximum height can be found by analyzing the vertex of the parabola represented by the equation $h(t) = -14t^2 + 56t$. The vertex formula for a parabola $y = ax^2 + bx + c$ is given by $(-b/2a, h(-b/2a))$. Here, $a = -14$ and $b = 56$, so the time at maximum height is $-56/(2*-14) = 2$ seconds. Plugging $t = 2$ into the equation gives $h(2) = -14(2)^2 + 56(2) = -56 + 112 = 56$ ft.

Solve the Problem 14ft14 \mathrm { ft }14ft Per Sec, Then Its Height (In Feet) Is Given By an Initial

Solve the Problem $14 \mathrm { ft }$ Per Sec, Then Its Height (In Feet) Is Given By an Initial