Find the sum.
-$\sum _ { i = 3 } ^ { 6 } \frac { \left( i ^ { 2 } - 3 \right) } { 2 }$
A) 39
B) 20
C) 74
D) 37

Question

Quizplus · Accepted Answer

The sum can be calculated by substituting the values of $i$ from 3 to 6 into the given formula and adding the results:For $i = 3$, the term is $\frac{(3^2 - 3)}{2} = \frac{(9 - 3)}{2} = \frac{6}{2} = 3$.For $i = 4$, the term is $\frac{(4^2 - 3)}{2} = \frac{(16 - 3)}{2} = \frac{13}{2} = 6.5$.For $i = 5$, the term is $\frac{(5^2 - 3)}{2} = \frac{(25 - 3)}{2} = \frac{22}{2} = 11$.For $i = 6$, the term is $\frac{(6^2 - 3)}{2} = \frac{(36 - 3)}{2} = \frac{33}{2} = 16.5$.Adding these terms together: $3 + 6.5 + 11 + 16.5 = 37$.

Find the Sum ∑i=36(i2−3)2\sum _ { i = 3 } ^ { 6 } \frac { \left( i ^ { 2 } - 3 \right) } { 2 }∑i=36​2(i2−3)​

Find the Sum $\sum _ { i = 3 } ^ { 6 } \frac { \left( i ^ { 2 } - 3 \right) } { 2 }$