Factor completely. If the polynomial cannot be factored, write ʺprime.ʺ
-$x ^ { 5 } y ^ { 2 } - 6 x ^ { 4 } y ^ { 3 } - 16 x ^ { 3 } y ^ { 4 }$
A) $x ^ { 3 } y ^ { 2 } ( x - 8 y ) ( x + y )$
B) $x ^ { 3 } y ^ { 2 } ( x + y ) ( x - 2 y )$
C) $x ^ { 3 } y ^ { 2 } ( x - 8 y ) ( x + 2 y )$
D) $x ^ { 3 } y ^ { 2 } ( x + 8 y ) ( x - 2 y )$

Question

Quizplus · Accepted Answer

The common factor in all terms is $x^3y^2$, so we can factor that out to get $x^3y^2(x-8y-2y)$. Simplifying the expression in the parentheses gives us $x-10y$ which is the only choice that matches this factorization. Therefore, the answer is choice C.

Factor Completely x5y2−6x4y3−16x3y4x ^ { 5 } y ^ { 2 } - 6 x ^ { 4 } y ^ { 3 } - 16 x ^ { 3 } y ^ { 4 }x5y2−6x4y3−16x3y4

Factor Completely $x ^ { 5 } y ^ { 2 } - 6 x ^ { 4 } y ^ { 3 } - 16 x ^ { 3 } y ^ { 4 }$