Factor completely. If the polynomial cannot be factored, write ʺprime.ʺ
-$$x ^ { 2 } - 10 x + 16$$
A) $( x - 2 ) ( x + 8 )$
B) $( x - 2 ) ( x - 8 )$
C) $( x + 2 ) ( x + 8 )$
D) $( x + 2 ) ( x - 8 )$

Question

Quizplus · Accepted Answer

The correct factorization is found by looking for two numbers that multiply to 16 and add to -10. Those numbers are -2 and -8, leading to the factorization $(x - 2)(x - 8)$.

Factor Completely x2−10x+16x ^ { 2 } - 10 x + 16x2−10x+16

Factor Completely $x ^ { 2 } - 10 x + 16$