Find the missing numerator and denominator.
-$$\frac { x + 6 } { x - 6 } \cdot \frac { ? } { ? } = \frac { ( x + 6 ) ( x - 1 ) } { ( x - 6 ) ( x + 7 ) }$$
A) $\frac { x + 1 } { x - 7 }$

B) $\frac { x - 1 } { x + 7 }$

C) $\frac { x ( 6 x - 1 ) } { x ( 6 x + 7 ) }$

D) $\frac { x ( x - 1 ) } { x ( x + 7 ) }$

Question

Find the missing numerator and denominator.
-$$\frac { x + 6 } { x - 6 } \cdot \frac { ? } { ? } = \frac { ( x + 6 ) ( x - 1 ) } { ( x - 6 ) ( x + 7 ) }$$
A) $\frac { x + 1 } { x - 7 }$

B) $\frac { x - 1 } { x + 7 }$

C) $\frac { x ( 6 x - 1 ) } { x ( 6 x + 7 ) }$

D) $\frac { x ( x - 1 ) } { x ( x + 7 ) }$

Quizplus · Accepted Answer

To find the missing numerator and denominator, we need to equate the numerators and denominators on both sides of the equation. Therefore, we get:
Numerator: $$x - 1$$ 
Denominator: $$x + 7$$ 
Thus, option B is the correct answer.

Find the Missing Numerator and Denominator x+6x−6⋅??=(x+6)(x−1)(x−6)(x+7)\frac { x + 6 } { x - 6 } \cdot \frac { ? } { ? } = \frac { ( x + 6 ) ( x - 1 ) } { ( x - 6 ) ( x + 7 ) }x−6x+6​⋅??​=(x−6)(x+7)(x+6)(x−1)​

Find the Missing Numerator and Denominator $\frac { x + 6 } { x - 6 } \cdot \frac { ? } { ? } = \frac { ( x + 6 ) ( x - 1 ) } { ( x - 6 ) ( x + 7 ) }$