Solve.
-$$a ^ { 2 } - 100$$
A) $( a - 10 ) ^ { 2 }$
B) $\left( a ^ { 2 } + 10 \right) \left( a ^ { 2 } - 10 \right)$
C) $( a + 10 ) ( a - 10 )$
D) $( a + 100 ) ( a - 100 )$

Question

Quizplus · Accepted Answer

This is a difference of squares, so it can be factored as $(a+10)(a-10)$. Option A is the square of a binomial, but with a different constant value than the one given in the expression. Option B is not a valid factorization since it does not simplify to the given expression. Option D is also a difference of squares, but with the wrong constant value. Therefore, the best choice is C.

Solve - a2−100a ^ { 2 } - 100a2−100 A) (a−10)2( a - 10 ) ^ { 2 }(a−10)2

Solve
- $a ^ { 2 } - 100$ A) $( a - 10 ) ^ { 2 }$