When a 25.00 mL sample of NaOH is titrated with 0.4523 M H₂SO₄, 36.69 mL of H₂SO4 solution is required to neutralize the NaOH.What is the molarity of the NaOH? A)0.3319 M B)0.6638 M C)1.328 M D)0.6164 M E)0.1988 M

Question

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First, we need to determine the number of moles of H₂SO4 used in the titration. Moles of H₂SO4 = Molarity x Volume Moles of H₂SO4 = 0.4523 M x 0.03669 L Moles of H₂SO4 = 0.0166 mol According to the balanced chemical equation for the reaction between NaOH and H₂SO4, the mole ratio of NaOH to H₂SO4 is 1:1. Therefore, the number of moles of NaOH used in the titration is also 0.0166 mol. Finally, we can calculate the molarity of the NaOH solution: Molarity of NaOH = Moles of NaOH / Volume of NaOH Volume of NaOH = 25.00 mL = 0.02500 L Molarity of NaOH = 0.0166 mol / 0.02500 L Molarity of NaOH = 0.664 M Therefore, the answer is (C) 1.328 M.

When a 2500 ML Sample of NaOH Is Titrated with 0