Rank the following 0.100 M solutions in order of increasing H₃O⁺ concentration: HCN, K_a = 6.2 x 10^-10; NH₄⁺, K_a = 5.6 x 10^-10; CH₃CO₂H, K_a = 1.8 x 10^-5 A)HCN

Question

Rank the following 0.100 M solutions in order of increasing H₃O⁺ concentration: HCN, K_a = 6.2 x 10^-10; NH₄⁺, K_a = 5.6 x 10^-10; CH₃CO₂H, K_a = 1.8 x 10^-5 A)HCN < NH₄⁺< CH₃CO₂H B)HCN < CH₃CO₂H < NH₄⁺ C)CH₃CO₂H < NH₄⁺< HCN D)CH₃CO₂H < HCN < NH₄⁺

Quizplus · Accepted Answer

To determine the order of increasing concentrations, we need to compare the values of Ksp for each compound. The compound with the lowest value of Ksp will have the lowest concentration of ions in solution, while the compound with the highest value of Ksp will have the highest concentration of ions in solution.

The Ksp values given in the problem are:
- HCN, Ksp = 6.2 x 10^-10
- NHS4, Ksp = 5.6 x 10^-10
- CH3COOH, Ksp = 1.8 x 10^-5

Comparing the Ksp values, we can see that HCN has the lowest value, indicating that it will have the lowest concentration of ions in solution. CH3COOH has the highest value, indicating that it will have the highest concentration of ions in solution. NHS4 has a Ksp value in between these two, indicating that it will have an intermediate concentration of ions in solution.

Therefore, the correct ranking from lowest to highest concentration is:
HCN < NHS4 < CH3COOH

The only answer choice that follows this ranking is B.

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