Solve the problem.
-The formula for converting Celsius temperature, C, to Fahrenheit temperature, F, is $$\mathrm { F } = \frac { 9 } { 5 } \mathrm { C } + 32 .$$
If Fahrenheit temperature ranges from $131 ^ { \circ }$ to $248 ^ { \circ }$, inclusive, what is the range for the Celsius temperature?
A) $\left[ 55 ^ { \circ } \mathrm { C } , 120 ^ { \circ } \mathrm { C } \right]$
B) $\left( 55 ^ { \circ } \mathrm { C } , 120 ^ { \circ } \mathrm { C } \right)$
C) $\left[ 268 ^ { \circ } \mathrm { C } , 478 ^ { \circ } \mathrm { C } \right]$
D) $\left( 268 ^ { \circ } \mathrm { C } , 478 ^ { \circ } \mathrm { C } \right)$

Question

Quizplus · Accepted Answer

To find the Celsius range, we use the formula $F = \frac{9}{5}C + 32$. For $F = 131$, solving for $C$ gives $C = \frac{5}{9}(131 - 32) = 55^\circ C$. For $F = 248$, solving for $C$ gives $C = \frac{5}{9}(248 - 32) = 120^\circ C$. Therefore, the range in Celsius is $[55^\circ C, 120^\circ C]$.

Solve the Problem F=95C+32.\mathrm { F } = \frac { 9 } { 5 } \mathrm { C } + 32 .F=59​C+32.

Solve the Problem $\mathrm { F } = \frac { 9 } { 5 } \mathrm { C } + 32 .$