Solve the Problem $v$ In Feet Per Second of an Object (Neglecting Air Resistance)

Solve the problem.
-A formula used to determine the velocity $v$ in feet per second of an object (neglecting air resistance) after it has fallen a certain height is $\mathrm { v } = \sqrt { 2 \mathrm { gh } }$ , where $\mathrm { g }$ is the acceleration due to gravity and $\mathrm { h }$ is the height the object has fallen. If the acceleration $g$ due to gravity on Earth is approximately 32 feet per second per second, find the velocity of a bowling ball after it has fallen 60 feet. (Round to the nearest tenth.)

A) $62.0 \mathrm { ft }$ per sec
B) $43.8 \mathrm { ft }$ per sec
C) $11.0 \mathrm { ft }$ per sec
D) $3840 \mathrm { ft }$ per sec