Solve the problem.
-There are 22 more sophomores than juniors in an 8 AM algebra class. If there are 46 students in this class, find the number of sophomores and the number of juniors in the class.
A)34 sophomores; 12 juniors
B)12 sophomores; 34 juniors
C)68 sophomores; 24 juniors
D)46 sophomores; 24 juniors

Question

Quizplus · Accepted Answer

Let the number of juniors be $j$. Then, the number of sophomores is $j + 22$. The total number of students is $j + (j + 22) = 46$. Solving this equation, $2j + 22 = 46$, we get $2j = 24$, so $j = 12$. Therefore, there are 12 juniors and $12 + 22 = 34$ sophomores.

Solve the Problem. -There Are 22 More Sophomores Than Juniors in an 8