Solve the problem.
-The length of a rectangular room is 6 feet longer than twice the width. If the room's perimeter is 156 feet, what are the room's dimensions?
A)Width = 24 ft; length = 54 ft
B)Width = 48 ft; length = 108 ft
C)Width = 36 ft; length = 42 ft
D)Width = 29 ft; length = 64 ft

Question

Quizplus · Accepted Answer

The problem can be solved by setting up equations based on the given information. Let the width be $w$ feet. Then, the length is $2w + 6$ feet. The perimeter of a rectangle is given by $2(length + width)$, so we have $2(w + 2w + 6) = 156$. Solving this equation gives $w = 24$ feet and the length $2(24) + 6 = 54$ feet.

Solve the Problem. -The Length of a Rectangular Room Is 6 Feet Longer