Model Exponential Growth and Decay
Solve.
-The value of a particular investment follows a pattern of exponential growth. In the year 2000 , you invested money in a money market account. The value of your investment t years after 2000 is given by the exponential growth model $\mathrm { A } = 5600 \mathrm { e } ^ { 0.055 \mathrm { t } }$. How much did you initially invest in the account?
A) $\$ 5600.00$
B) $\$ 5916.63$
C) $\$ 308.00$
D) $\$ 2800.00$

Question

Quizplus · Accepted Answer

The initial investment is found by evaluating the exponential growth model at $t = 0$, which gives $A = 5600e^{0.055(0)} = 5600e^0 = 5600$.

Model Exponential Growth and Decay Solve A=5600e0.055t\mathrm { A } = 5600 \mathrm { e } ^ { 0.055 \mathrm { t } }A=5600e0.055t

Model Exponential Growth and Decay
Solve $\mathrm { A } = 5600 \mathrm { e } ^ { 0.055 \mathrm { t } }$