Solve the system of equations.
-$$\begin{array} { l }
- 13 + 4 z = 3 ( x - 2 y ) \
3 ( x - 4 y - z ) = - 18 \
- 3 ( 2 x + y ) + 3 z = 6
\end{array}$$
A) $\{ ( - 1,1,1 ) \}$
B) $\{ ( - 1,3,1 ) \}$
C) $\{ ( - 1,3,3 ) \}$
D) $\{ ( - 1 , - 3,1 ) \}$

Question

Solve the system of equations.
-$$\begin{array} { l } 
- 13 + 4 z = 3 ( x - 2 y ) \
3 ( x - 4 y - z ) = - 18 \
- 3 ( 2 x + y ) + 3 z = 6
\end{array}$$
A) $\{ ( - 1,1,1 ) \}$
B) $\{ ( - 1,3,1 ) \}$
C) $\{ ( - 1,3,3 ) \}$
D) $\{ ( - 1 , - 3,1 ) \}$

Quizplus · Accepted Answer

Solving the system of equations simultaneously, we find that the solution is $x = -1$, $y = 1$, and $z = 1$, which corresponds to choice A.

Solve the System of Equations −13+4z=3(x−2y)3(x−4y−z)=−18−3(2x+y)+3z=6\begin{array} { l } - 13 + 4 z = 3 ( x - 2 y ) \\3 ( x - 4 y - z ) = - 18 \\- 3 ( 2 x + y ) + 3 z = 6\end{array}−13+4z=3(x−2y)3(x−4y−z)=−18−3(2x+y)+3z=6​

Solve the System of Equations $\begin{array} { l } - 13 + 4 z = 3 ( x - 2 y ) \\3 ( x - 4 y - z ) = - 18 \\- 3 ( 2 x + y ) + 3 z = 6\end{array}$