Solve the system of equations.
-$$\begin{array} { c }
x + y + z = 10 \
x - y + 3 z = 4 \
3 x + y + z = 16
\end{array}$$
A) $\{ ( 3,5,2 ) \}$
B) $\{ ( 5,3,2 ) \}$
C) $\{ ( 2,5,3 ) \}$
D) $\{ ( 2,3,5 ) \}$

Question

Solve the system of equations.
-$$\begin{array} { c } 
x + y + z = 10 \
x - y + 3 z = 4 \
3 x + y + z = 16
\end{array}$$
A) $\{ ( 3,5,2 ) \}$
B) $\{ ( 5,3,2 ) \}$
C) $\{ ( 2,5,3 ) \}$
D) $\{ ( 2,3,5 ) \}$

Quizplus · Accepted Answer

Solving the system of equations by either substitution or elimination method, we find that $x = 3$, $y = 5$, and $z = 2$, which matches option A.

Solve the System of Equations x+y+z=10x−y+3z=43x+y+z=16\begin{array} { c } x + y + z = 10 \\x - y + 3 z = 4 \\3 x + y + z = 16\end{array}x+y+z=10x−y+3z=43x+y+z=16​

Solve the System of Equations $\begin{array} { c } x + y + z = 10 \\x - y + 3 z = 4 \\3 x + y + z = 16\end{array}$