Solve the system of equations by the substitution method.
-$$\begin{array} { l }
5 x - 6 y = 2 - 5 x \
2 x + 6 y = x + 5 y + - 3
\end{array}$$
A) $\{ ( - 1 , - 2 ) \}$
B) $\{ ( - 1,2 ) \}$
C) $\{ ( 0,2 ) \}$
D) $\left\{ \left[ \frac { 1 } { 5 } , 0 \right\} \right\}$

Question

Solve the system of equations by the substitution method.
-$$\begin{array} { l } 
5 x - 6 y = 2 - 5 x \
2 x + 6 y = x + 5 y + - 3
\end{array}$$
A) $\{ ( - 1 , - 2 ) \}$
B) $\{ ( - 1,2 ) \}$
C) $\{ ( 0,2 ) \}$
D) $\left\{ \left[ \frac { 1 } { 5 } , 0 \right\} \right\}$

Quizplus · Accepted Answer

First, simplify both equations: 1) $10x = 2$, so $x = \frac{1}{5}$. 2) Substituting $x = \frac{1}{5}$ into the second equation gives $y = -2$. Thus, the solution is $(-1, -2)$.

Solve the System of Equations by the Substitution Method 5x−6y=2−5x2x+6y=x+5y+−3\begin{array} { l } 5 x - 6 y = 2 - 5 x \\2 x + 6 y = x + 5 y + - 3\end{array}5x−6y=2−5x2x+6y=x+5y+−3​

Solve the System of Equations by the Substitution Method $\begin{array} { l } 5 x - 6 y = 2 - 5 x \\2 x + 6 y = x + 5 y + - 3\end{array}$